Input file:
$ cat file.txt
500:120:100
100:120:700
200:900:125
120:120:900
Required:
Compute the sum of individual columns of the above file. i.e. required output:
920:1260:1825
Awk solution - 1:
$ awk 'BEGIN {FS=OFS=":"}
NR == 1 { n1 = $1; n2 = $2; n3 = $3; next }
{ n1 += $1; n2 += $2; n3 += $3 }
END { print n1, n2, n3 }' file.txt
Output:
920:1260:1825
Awk solution - 2:
$ awk -F ":" '
{ for (i=1; i<=NF; ++i) sum[i] += $i; j=NF }
END { for (i=1; i <= j; ++i) printf "%s ", sum[i]; printf "\n"; }
' file.txt
Output:
920 1260 1825
And the solution for finding sum of numbers in each row of a file (i.e. horizontal sum) is here
Posts
2 comments:
I appreciate your posts on this and a similar post on 3/24/2010.
Here is my scenario, I have two columns. I need to add the first columns (the easy part). The second column is a percent that I need to subtract by 100 then multiply against $1 for each line, then sum them
Here is the input:
942330863 96
942172150 95
942099452 92
I need this as an output:
2826602465 160169797
I tried this code, but it's just doing the percentage work and only doing it for the first line and not summing every line.
awk '
BEGIN {FS=","}
NR == 1{ n1 = $1; x = substr((100-$2)/100,2,3); y = x*$2; next }
{ n1 += $1; y += $y }
END { printf ("%-15d%d\n",n1,y)
}'
@Mike M:
I think this is the problem:
y += $y
should be
y += y
?
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