Filter line using Awk split function

Input file "file.txt" has data in the following format:

$ cat file.txt
232323 90 /T/1382/8558/365p/133 100 234 679
S/1234 90 /N/1389/5000/365s/5000 800 134 679
792363 80 /T/1381/9858/365q/133 100 234 779
136383 90 /K/1382/5000/365p/5000 500 934 979
136383 90 /T/1382/5000/279p/9000 100 134 601

Required output: From the above file print only the lines whose 3rd field has the value "5000" as the 4th field (separated by the delimiter "/") in it. i.e. required output:

S/1234 90 /N/1389/5000/365s/5000 800 134 679
136383 90 /K/1382/5000/365p/5000 500 934 979
136383 90 /T/1382/5000/279p/9000 100 134 601

Using awk:

$ awk '{
    split($3,arr,"/")
    if(arr[4] == 5000) {
        print $0
        }
}' file.txt

The awk function split(s,a,sep) splits a string "s" into an awk array "a" using the delimiter "sep".

A simple UNIX bash script to solve this:

$ while read line
    do 
        thirdf=$(echo "$line" | awk '{print $3}')
        fourthf=$(echo "$thirdf" | awk -F "/" '{print $4}')
        [ "$fourthf" -eq 5000 ] && echo $line
done < file.txt

Related posts:
- Add prefix to lines in a file using awk and bash
- Replace n-th occurrence of pattern in a file using Awk